5 less than three times a number is 10

Answers

Answer 1
5•2=10
2 is less then 3
Answer 2

3x-5 =10

 add 5 to both sides

3x=15

 divide both sides by 3

x=5


check:

3(5)-5 = 15-5 = 10


Related Questions

the age of two groups of yoga students are shown in the following dot plot

Answers

Since the mean absolute deviation (MAD) is lower for group P, this means that group P has less variability compared to group Q.

The answer is choice A.

A triangle has one side that measures x, and the other two sides each measure 4 inches less than x. The perimeter is 19 inches.

What is the measure of x?

Answers

perimeter of a triangle = all 3 sides added together

x + (x - 4) + (x - 4) = 19
3x - 8 = 19
3x = 19 + 8
3x = 27
x = 27/3
x = 9 <==

Answer: Simplified version of the answer above: (x = 9) is the correct answer.

Step-by-step explanation:

find the solution of the system of equations 2x-4y=32 2x-8y=48

Answers

2x-4y=32
2x-8y=48
--------------subtract
4y = - 16
y  = -4

2x-4y=32 
2x- 4(-4)=32 
2x + 16 = 32
2x = 16
x = 8

answer
(8, -4)
2x - 4y = 32
2x - 8y = 48

Multiple equation 2 by -1 so the 'x' variables will cancel.
-1(2x - 4y = 32)
-2x + 4y = - 32
 2x - 8y = 48
-------------------- add
     - 4y = 16      divide both sides by -4
         y = -4
Plug -4 back into either equation and solve for y.
2x - 4y = 32
2x -4(-4) = 32
2x + 16 = 32  subtract 16 from both sides
2x = 16          divide both sides by 2
x = 8
(8, -4)

Which expression is equivalent to 6(14)? 6(10 + 4) 6(10 + 14) 6(1 + 40) 6(10 + 40)

Answers

The first one because of you add 10 and 4 you get 14. And they both multiply 6 by 14.

5. Suppose a railroad is 2 km long, and it expands on a hot day by 50 cm in length. Approximately how high would the center of the rail rise above the ground? (Hint: Convert all measurements to meters BEFORE calculating any values)

Answers

The original length of the railroad is
L₁ = 2 km = 2000 km

The extended length after expansion is
L₂ = L₁ + 50 cm 
    = 2000 + 0.5
    = 2000.5 m

Assume that the deflected shape is a circle with radius = r, as shown in the figure below.
The central angle of the deflected shape is 2θ.
The deflected length is calculated as
2rθ = L₂.
That is
rθ = 2000.5/2 = 1000.25 
r = 1000.25/θ                        (1)

By definition (from the figure)
sinθ = 1000/r                        (2)

Substitute (1) into (2).
sin θ = (1000 θ)/1000.25 = 0.99975 θ
To find θ, define the function
f(θ) = 0.99975 θ - sin θ
A graphical solution from the calculator yields
θ = 0.0038 rad.
Therefore from (1), obtain
r = 263223.7 m

The height of the center of the rail above ground is
h = r - r cos θ = r(1 - cos θ)
   = 263223.7(1 - cos(0.0038))
   = 1.9 m

Answer: 1.9 m

To find the height at which the center of a railroad rail would rise due to expansion, convert all measurements to meters and use the formula h ≈ ΔL / 8. For expansion of 50 cm, the rail would rise approximately 6.25 cm.

The student has asked how high the center of a 2 km long railroad rail would rise when it expands by 50 cm on a hot day. First, we need to convert all measurements to meters: the railroad is 2000 m long, and it expands by 0.50 m. To find the height that the rail would rise, we can consider the rail as forming an arc of a circle after expansion.
We have the original length of the rail as the diameter of the circle and the expanded length as a slightly longer arc of the same circle. As the increase in length due to expansion is very small compared to the original length, we can use the approximation that the height of the rise is equal to the arc's excess length divided by 8 (h ≈ ΔL / 8).

Applying this formula: h ≈ 0.50 m / 8 = 0.0625 m or 6.25 cm. This approximation works under the assumption that the bend in the rail is mild, as it would be in reality due to the small degree of expansion.

BEST ANSWER GETS BRAINLIEST
The following data show the height, in inches, of 11 different garden gnomes:

2 9 1 23 3 7 10 2 10 9 7

After removing the outlier, what does the mean absolute deviation of this data set represent?

A, On average, the height of a garden gnome varies 3.2 inches from the mean of 7 inches.
B, On average, the height of a garden gnome varies 3.6 inches from the mean of 6 inches.
C, On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
D, On average, the height of a garden gnome varies 3.6 inches from the mean of 7 inches.

Answers

In doing experiments, it is sometime inevitable to commit errors. This is reflected on the set of data points that you have. When you notice that there is an absolute unique point that is very different from the rest, that is the outlier. In this data set, the outlier is 23. You remove the outlier from the data set so as not to significantly affect your results. 

The average or mean, therefore, is

μ = Σx/N = (2+9+1+3+7+10+2+10+9+7)/10
μ = 6

The equation for the mean absolute deviation is

MAD = ∑|x-μ|/N
MAD = [|2-6|+|9-6|+|1-6|+|3-6|+|7-6|+|10-6|+|2-6|+|10-6|+|9-6|+|7-6|]/10
MAD = 3.2

Therefore, the answer is C.

The two jar are geometrically similar.The height are 25cm and 10cm.The diameter of the larger jar is 7.5cm.Find the diameter of the smaller jar.

Answers

25/10 = 7.5/x

75/25x

x=75/25 = 3

diameter of smaller jar = 3 cm

F^(-1) when f(x)=2x-7/3

Answers

y=2x-7/3
x=2y-7/3
x+7/3=2y-7/3+7/3
(x+7/3)/2=2y/2
(x+7/3)/2= f^-1(x)

Use a calculator to evaluate 8 · cos30° rounded to four decimal places.

Answers

Cos(30) • 8 = 6.9282-0323

Answer:

The value of 8 cos 30° rounded to four decimal places = 6.9282

Step-by-step explanation:

Here we need to find the value of 8 cos 30° rounded to four decimal places.

Using the calculator to find the value

          8 cos 30° = 6.9282032302755

Rounding the number to   four decimal places, we will get

         8 cos 30° = 6.9282

The value of 8 cos 30° rounded to four decimal places = 6.9282

Which number is equivalent to the fraction 18/5

Answers

(18/5)(2/2)=36/10=3.6
18/5 = 36/10
Multiply two to both numerator and denominator and the answer would be 36/10 and when simplified 18/5.

Part A: Solve −np − 90 < 30 for n. Show your work. (4 points) Part B: Solve 5m − 3h = 45 for h. Show your work. (6 points)

Answers

Hello there!

Part A: Solve for n; -n*p - 90 < 30
Add 90 to both sides.
-n*p < 120
Divide both sides by p.
-n < 120/p
Divide both sides by -1.
n [tex] \geq [/tex] 120/-p is your answer for part A.

Part B: Solve for h; 5m - 3h = 45
Subtract 5m from both sides.
-3h = -5m + 45
Divide both sides by -3.
h = (-5m + 45)/-3 is your answer for part B.

I hope this helps!

A decorator adds vases to a mantle to decorate. She wants to use 2 matching green vases, 3 matching blue vases, and 4 matching white vases. Find the total number of arrangements of vases that can be made.

288

140

1,260

362,880

Answers

There are 2 green, 3 blue, and 4 white vases.
The green vases can be arranged in 2! = 2*1 = 2 ways.
The blue vases can be arranged in 3! = 3*21 = 6 ways.
The white vases can be arranged in 4! = 4*3*2*1 = 24 ways.

The total number of arrangements is
2*6*24 = 288

Answer: 288

Answer:

1,260

Step-by-step explanation:

Because it seemed right and I'm pretty sure it is

The average annual salary of the employees of a company in the year 2005 was $80,000. It increased by the same factor each year and in 2006, the average annual salary was $88,000. Let f(x) represent the average annual salary, in thousand dollars, after x years since 2005. Which of the following best represents the relationship between x and f(x)?

f(x) = 88(0.88)x
f(x) = 88(1.1)x
f(x) = 80(0.88)x
f(x) = 80(1.1)x

Answers

the answer is f(x)=80(1.1)x

Answer: [tex]f(x) = 80 ( 1.1 ) ^x[/tex]

Step-by-step explanation:

Let the function that shows the average annual salary after x years since 2005 is,

[tex]f(x) = ab^x[/tex] ----- (1)

Where a and b are any unknown numbers.

For x = 0,

[tex]f(0) = ab^0= a[/tex]

But According to the question,

The average annual salary of the employees of a company in the year 2005 was $80,000.

Therefore, f(0)=80000 dollars.

⇒ a = 80000

From equation (1),

[tex]f(x) = 80000 b^x[/tex]  ------- (2)

Now again according to the question,

In 2006, the average annual salary was $88,000

But the average annual salary in 2006 is [tex]f(1) = 80000 b^1[/tex]

⇒ [tex] 80000 b^1=88000[/tex]

⇒ b = 1.1

Putting the value of b in equation (2),

The average annual salary after x years since 2005 is,

[tex]f(x) = 80000 (1.1)^x[/tex] dollars

Or  [tex]f(x) = 80 (1.1)^x[/tex] thousand dollars

Thus, Fourth Option is correct.


Simplify (−34.67)0.
−34.67
−1
0
1

Answers

Im pretty sure that it's 0

Answer:

The answer is 1.

Im sorry I forgot the step by step explanation, but I had this in a quuiz a while ago and the answer is 1.

A store had 235 MP3 players in the month of January. Every month ,30% of the MP3 players were sold and 50 new MP3 players were stocked in the store. Witch recursive best represents the number of MP3 players in the store f(n) after n months?

Answers

f(n)=235-(235*.3^n)+50n is your equation where * is multiplication and ^ it to the power to.

Solve the following system of equations by substitution. 3x + 2y = -12 x = 2 A. (2, -9) B. (-2, -3) C. (3, 2) D. (2, 3)

Answers

Plugging it in, we get (3)(2)+2y=-12 and 6+2y=-12. Subtracting 6 from both sides, we get -18=2y and dividing by 2 we get y=-9  to get (2, -9) since x is first in the pair

How many ​​60 degree angles does it take to make a full turn??

Answers

it takes 3 times 60 degree angles

Answer:

6

Step-by-step explanation:

60x 6 =360

Plz give me 5 stars and a THANK YOU!

The Moon is about 240,000 miles from the Earth what is the distance written as a whole number multiplied by a power of 10

Answers

here is the answer :
2,4 x 10^5
2.4 X 10 to the 5th i believe

Why can't irrational numbers be whole numbers

Answers

Irrational numbers cannot be represented by a ratio of two integers.

All whole numbers, however, can. This can be done by placing the number over 1. For example 0/1, 34/1, 173635278/1.

Solve for x: the quantity of x plus 4 all over 2 = 7.

x = 3
x = 5
x = 6
x = 10

Answers

the actual answer is 10 , 10 plus 4 is 14 and 14 divided by 2 equals 7 so the answer is 10
 i hope this helped

Each of the four outside walls of the large wooden box shown above is to be covered with waterproof plastic that comes in 3-foot-wide rolls. The plastic does not overlap. What is the total length, in feet, of plastic, needed to cover the four walls?

A) 21 ft
B) 42 ft
C) 63 ft
D) 84 ft
E) 126 ft

Explain too, thanks.

Answers

we need the lateral aera
that will be
LA=2H(L+W)

H=6
L=12
W=9
LA=2(6)(12+9)
LA=12(21)
LA=252

so we need 252 square feet
it comes in 3ft width so
3ft times ?=252
divide both sides by 3ft
?=84

we need 84ft of that wrap

D is answer

A bag contains nickels, quarters and pennies. If a handful of coins brings in five nickels, 3 quarters, and nine pennies, how much money is expected to be in the bag if 90 coins are in the bag?

Answers

The expected amount of money in the bag if 90 coins are in the bag is [tex]\(\$5.78\)[/tex].

We need to determine the total value of the coins in the bag based on the given handful and then extrapolate that to the total number of coins in the bag.

First, let's calculate the value of the coins in the handful:

The value of five nickels is [tex]\(5 \times 5\)[/tex] cents = 25 cents.

The value of three quarters is [tex]\(3 \times 25\)[/tex] cents = 75 cents.

The value of nine pennies is [tex]\(9 \times 1\)[/tex] cent = 9 cents.

Adding these values together gives us the total value of the handful:

[tex]\[25 + 75 + 9 = 109 \text{ cents}\][/tex]

Next, we need to find out the ratio of each type of coin in the handful. We have a total of [tex]\(5 + 3 + 9 = 17\)[/tex] coins in the handful.

The ratios for each type of coin are as follows:

Nickels: [tex]\(\frac{5}{17}\)[/tex]

Quarters: [tex]\(\frac{3}{17}\)[/tex]

Pennies: [tex]\(\frac{9}{17}\)[/tex]

Now, let's calculate the expected number of each type of coin in the bag, given that there are 90 coins in total:

Expected nickels: [tex]\(90 \times \frac{5}{17}\)[/tex]

Expected quarters: [tex]\(90 \times \frac{3}{17}\)[/tex]

Expected pennies: [tex]\(90 \times \frac{9}{17}\)[/tex]

Using these ratios, we can calculate the expected number of each coin type:

Expected nickels: [tex]\(90 \times \frac{5}{17} \approx 26.47\)[/tex], but since we can't have a fraction of a coin, we'll consider 26 nickels.

Expected quarters: [tex]\(90 \times \frac{3}{17} \approx 15.88\)[/tex], rounding to 16 quarters.

Expected pennies: [tex]\(90 \times \frac{9}{17} \approx 47.65\)[/tex], rounding to 48 pennies.

Finally calculate the total expected value in the bag by multiplying the number of each type of coin by its value:

Value of expected nickels: [tex]\(26 \times 5\)[/tex] cents = 130 cents

Value of expected quarters: [tex]\(16 \times 25\)[/tex] cents = 400 cents

Value of expected pennies: [tex]\(48 \times 1\)[/tex] cent = 48 cents

Adding these values together gives us the total expected value in the bag:

[tex]\[130 + 400 + 48 = 578 \text{ cents}\][/tex]

To convert the total value from cents to dollars, we divide by 100:

[tex]\[578 \text{ cents} \div 100 = \$5.78\][/tex]

The net of square pyramid is shown below. What is the surface area of the pyramid ?

Answers

To find surface area, find the area of the net like you would for a composite figure.
For the square, area is length times width.
8*8=64
For the triangles, area is bh/2
8*8/2=32
Since there are four triangles of the same area, multiply by 4.
32*4=128

Add these values
128+64=192 cm^2

Final answer: D
this is the answer
192

PLZZZ HELP WILL GIVE BRAINLIESTTTT

Answers

10 is the missing number.

What are the discontinuities of the function f(x) = the quantity of x squared plus 5 x plus 6, all over 2 x plus 16. ?

Answers

Since f(x) = (x^2 + 5x + 6) / (2x + 16)

For discontinuities, they can be found at where the slope does NOT exist

Take the derivative of f(x):

f'(x) = (x^2 + 16x + 34) / 2(x+8)^2

Apparently, when x= -8, f'(x) is NOT defined

Therefore, the discontinuity is uniquely located at x = -8

Answer:

Step-by-step explanation:

Since f(x) = (x^2 + 5x + 6) / (2x + 16)

For discontinuities, they can be found at where the slope does NOT exist

Take the derivative of f(x):

f'(x) = (x^2 + 16x + 34) / 2(x+8)^2

Apparently, when x= -8, f'(x) is NOT defined

Therefore, the discontinuity is uniquely located at x = -8

The averge temperature in Fairbanks, Alaska, in november is 2°F above zero. Write thiis temperture as an integer

Answers

Answer:  "2" .
_________________________________________________

Answer: Answer is 2

Step-by-step explanation:

What value does 4 represent in the number 487.009

Answers

400 is the answer :)                                                     
The answer to this question is 400

What is the range of y=sec x

Answers


y≤-1, y≥1 is the range of y=sec x

The values where cos(x) is equal to 0 are excluded from the domain of the function y=sec(x)=1cos(x), or the values 2+n for all integers n. The function's range is either y<=1 or y>=1.

What is  domain?

The domain of a function is the set of values that we are allowed to plug into our function. This set is the x values in a function such as f(x).

here, we have,

we know that  "secant function" mean:

Its root is the Latin verb secare, which means "to cut." Any line that intersects a circle twice is referred to as a secant line, and you can conceive of this line as slicing the circle in half. The distance from the origin to the point where the tangent line intersects the x-axis is the secant function.

now,  the identity of the sec is:

1/cos(x) = sec(x) Cot (x) = 1/Tan (x)

To know more about domain visit:-

brainly.com/question/28135761

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Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left. How many digital cameras did he have first?

Answers

Mr. Rif-kin initially had 181 digital cameras.

Let's denote:

- [tex]\( x \)[/tex] as the initial number of digital cameras.

- [tex]\( y \)[/tex] as the initial number of manual cameras.

According to the given information:

1. Mr. Rif-kin had a total of 240 digital and manual cameras initially:

[tex]\[ x + y = 240 \][/tex]

2. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left:

[tex]\[ (x - 82) = 3(y - 26) \][/tex]

We can set up a system of equations with these two equations and solve for [tex]\( x \)[/tex] and [tex]\( y \)[/tex].

1. From Equation 1:

[tex]\[ y = 240 - x \][/tex]

2. Substituting [tex]\( y \)[/tex] from Equation 1 into Equation 2:

[tex]$\begin{aligned} & x-82=3((240-x)-26) \\ & x-82=3(214-x) \\ & x-82=642-3 x \\ & 4 x=724 \\ & x=181\end{aligned}$[/tex]

Now that we have found [tex]\( x \)[/tex], we can find [tex]\( y \)[/tex] using Equation 1:

[tex]$\begin{aligned} & y=240-x \\ & y=240-181 \\ & y=59\end{aligned}$[/tex]

So, Mr. Rif-kin initially had [tex]\( 181 \)[/tex] digital cameras and [tex]\( 59 \)[/tex] manual cameras.

The complete question is here:

Mr. Rif-kin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left. How many digital cameras did he have at first?

In a box-and-whisker plot, the interquartile range is a measure of the spread of the middle half of the data. Find the interquartile range for the data set: 10, 3, 7, 6, 9, 12, 13

Answers

In statistics, it is imperative to arrange your data entries from least to greatest. That would be the first step of our solution

3  6  7  9  10  12  13

Interquartile range is the difference of the last quartile to the first quartile. Divide your entire data set into four parts. Each division is called a quartile. Its numerical value is the average of its numbers. However, since our data set contains 7 numbers, which is odd, we write the median (middle value) twice. The quartiles are:

3  6 |  7  9 | 9  10 |  12  13

Q₁= (3+6)/2 = 4.5
Q₂ = (7+9)/2 = 8
Q₃ = (9+10)/2 = 9.5
Q₄ = (12+13)/2 = 12.5

The interquatile range is Q₄ - Q₁ = 12.5 - 4.5 = 8
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