what is
4 group of _ tenths is 2.8
What is 45122 to the nearest ten thousand
Solve the equation. 0.7+y=−1.34
Just subtract 0.7 from 1.34
y = -2.04
Hope this help
Answer: The required solution is x = -2.04.
Step-by-step explanation: We are given to solve the following linear equation :
[tex]0.7+y=-1.34~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
To solve the given equation, we must find the value of the unknown variable y.
The solution of equation (i) is as follows :
[tex]0.7+y=1.34\\\\\Rightarrow y=-1.34-0.7\\\\\Rightarrow y=-2.04.[/tex]
Thus, the required solution is x = -2.04.
Solve for A, 4(2a+3)=-3(a-1)+31
is math related to science ?
Math Please Help!!!!
Susan and Mark are standing at different places on a beach and watching a bird. The angles of elevation they make are 20º and 50º, respectively. If Susan and Mark are 7 kilometers apart and the bird is between them, the bird is at a height of kilometers from the ground. NextReset
Answer:
The bird is at a height of 1.95 km from the ground.
Step-by-step explanation:
It is given that the distance between susan and mark is 7 km and bird is between susan and mark. The angles of elevation they make are 20º and 50º, respectively.
Draw a perpendicular line from the bird on base.
Let the distance of susan from and the altitude be x.
In triangle ABS,
[tex]tan(20^{\circ})=\frac{AB}{x}[/tex]
[tex]tan(20^{\circ})x=AB[/tex]
[tex]0.364x=AB[/tex] ..... (1)
In triangle ABM,
[tex]tan(50^{\circ})=\frac{AB}{7-x}[/tex]
[tex]1.192(7-x)=AB[/tex] ..... (2)
From (1) and (2), we get
[tex]0.364x=1.192(7-x)[/tex]
[tex]1.556x=8342[/tex]
[tex]x=5.36[/tex]
The length of AB is,
[tex]AB=0.364(5.36)=1.95147\approx 1.95[/tex]
Therefore, the he bird is at a height of 1.95 km from the ground.
By showing your work what is the answer to 0.96÷0.144=
Answer:
Recognize that both 0.96 and 0.144 are divisible by 12:
(0.96/12) / (0.144/12) = 0.08 / 0.012. This reduces to 0.02 / 0.003, or
20/3 or approx. 6.666.
You could also begin by eliminating the decimal fractions. Mult. 0.96 and 0.144 each by 1000 results in 960/144.
Since both 960 and 144 can be divided evenly by 24, we get 40 and 6.
40/6 = 20/3, or approx. 6.666, as before.
Step-by-step explanation:
290 in expanded notation
This is the answer. 200 + 90 + 0
The place value chart can help us to write a number in expanded notation. When we put 290 into the place value chart, we can recognize that our number is equal to
2 hundreds + 9 tens + 0 units
Image is provided.
Round 992,449 to the nearest hundred thousand
Suppose Georgette buys 400 shares of Google at $250 a share. She sells them at $350 a share. What is her capital gain?
A rectangular piece of gift wrap is 5.5 inches by 2.1 inches what is the area of the gift wrap? ( Hint: use A=lxw
Juanita is making necklaces to give as presents. She plans to put 15 beads on each necklace. Beads are sold in packages of 20. What is the least common number of packages she can buy to make necklaces and have no beads left over?
Answer: 3
Step-by-step explanation:
Given : Juanita is making necklaces to give as presents.
She plans to put 15 beads on each necklace. Beads are sold in packages of 20.
To find the least common number of packages she can buy to make necklaces and have no beads left over, First we need to find the least common multiple of 15 and 20.
Since , [tex]15=3\times5\\\\20=2\times2\times5[/tex]
Then least common multiple of 15 and 20 =[tex]2\times2\times3\times5=60[/tex]
Now, the least common number of packages she can buy to make necklaces and have no beads left over =[tex]\dfrac{60}{20}=3[/tex].
Hence, the least common number of packages she can buy to make necklaces and have no beads left over=3
Multiply and simplify -12i x 3i
Olivia has taken out a $13,100 unsubsidized Stafford loan to pay for her college education. She plans to graduate in four years. The loan has a duration of ten years and an interest rate of 7.6%, compounded monthly. By the time Olivia graduates, how much greater will the amount of interest capitalized be than the minimum amount that Olivia could pay to prevent interest capitalization? Round all dollar values to the nearest cent.
a. $654.45
b. $477.27
c. $995.60
d. $354.22
If Olivia wants to prevent interest capitalization, she must pay the accrued interest each month. That amount is
... I = Prt = $13,100×0.076×(1/12) = $82.97
Over 4 years (48 months), these payments total $82.97×48 = $3982.56.
_____
If no payments are made, the loan balance grows by the multiplier (1 +r/12) each month. Then the amount of interest that will be capitalized at the end of 48 months is ...
... $13,100×((1 +0.076/12)^48 -1) = $4637.01
The difference in these amounts is ...
... $4637.01 -3982.56 = $654.45 . . . . . matches selection a.
Answer:
A
Step-by-step explanation:
654.45
What is the markup for a pair of hiking boots that the store buys for $80 each if the markup rate is 15%?
Final answer:
To find the markup on a pair of hiking boots with a cost of $80 and a 15% markup rate, multiply the cost by 0.15 to get a $12 markup. The selling price would then be $80 + $12, totaling $92.
Explanation:
To calculate the markup for a pair of hiking boots that the store buys for $80 with a markup rate of 15%, first convert the percentage to a decimal by dividing by 100.
Markup rate as a decimal: 0.15
Next, multiply the cost price by the decimal.
Markup amount = Cost price × Markup rate
Markup amount = $80 × 0.15
Markup amount = $12
So, the markup on the hiking boots is $12. To find the selling price, you add the markup to the cost price:
Selling price = Cost price + Markup amount
Selling price = $80 + $12
Selling price = $92
The store would sell the hiking boots for $92.
What percentage of the participants lie within one standard deviation unit of the mean (i.e., on both sides of the mean) in a normal distribution?
The distance between Maggie’s home and her school is 5,280 yards. (Hint: 1 mile = 1,760 yards.)
Answer:
The answer is 10,560 yards and 6 miles. The 5,280 yards is just from her home to the school. So you multiply it by 2 and divide by 1760.
Step-by-step explanation:
Suppose you randomly select a letter from BURGER AND STARBIRD. Imagine writing these letters on Ping- Pong balls—one letter per ball—then putting them all in a barrel and remov- ing one. What is the probability of pulling out an R?
What's the value of the 8's in 88,000
Two angles are supplementary. One angle measures 50 degrees more than the other angle. Find the measure of the larger angle?
Final answer:
Using algebra, the larger of two supplementary angles, where one is 50 degrees more than the other, is found to be 115 degrees.
Explanation:
To solve for the measure of the larger angle in a pair of supplementary angles, where one angle measures 50 degrees more than the other, we can use algebra. If we let x represent the measure of the smaller angle, then the larger angle will be x + 50 degrees. Since supplementary angles sum up to 180 degrees, we can set up the equation x + (x+50) = 180.
Solving this equation:
Combine like terms: 2x + 50 = 180
Subtract 50 from both sides: 2x = 130
Divide by 2: x = 65
Since x is the measure of the smaller angle, the larger angle measures x + 50, which is 65 + 50 = 115 degrees.
Therefore, the measure of the larger angle is 115 degrees.
(2.03)
Below are the steps to solve an equation:
Step 1: |x − 2| + 3 = 7
Step 2: |x − 2| = 7 − 3
Step 3: |x − 2| = 4
Which of the following is a correct next step to solve the equation? (1 point)
You have a 5 question multiple choice test. Each question has four choices. You don’t know any of the answers. What is the experimental probability that you will guess exactly three out of five questions correctly?
Type your answer below using complete sentences.
There are two lakes in town of Roxbury. Lake Big Rock is 1650 ft longer than Little Lake Rock. Together, they are 5273 ft long. How long is each lake? Please show work.
Little Lake Rock is 1811.5 feet long, and Lake Big Rock is 3461.5 feet long.
Let's use algebra to solve this problem.
Let L be the length of Little Lake Rock in feet, and let B be the length of Lake Big Rock in feet.
We are given two pieces of information:
Lake Big Rock is 1650 ft longer than Little Lake Rock: B = L + 1650.
Together, they are 5273 ft long: B + L = 5273.
Now, we have a system of two equations with two variables:
B = L + 1650
B + L = 5273
We can use the first equation to express B in terms of L and then substitute this expression into the second equation:
B = L + 1650
Now, substitute B in the second equation:
(L + 1650) + L = 5273
Combine like terms:
2L + 1650 = 5273
Subtract 1650 from both sides:
2L = 5273 - 1650
2L = 3623
Now, divide by 2 to find the length of Little Lake Rock (L):
L = 3623 / 2
L = 1811.5 feet
Now that we know the length of Little Lake Rock, we can find the length of Lake Big Rock using the first equation:
B = L + 1650
B = 1811.5 + 1650
B = 3461.5 feet
So, Little Lake Rock is 1811.5 feet long, and Lake Big Rock is 3461.5 feet long.
for such more question on length
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The nurse researcher is reading about linear regression. what is linear regression
Factor the polynomial completely
24x^2y-6y
What is the equation of the line that goes through (3,11) and is parallel to the line 2x-y=5
867,000 rounded to the nearest hundred thousand
The table shows the cost of a ski rental package for a given number of people. People Cost ($) 4 160 5 200 6 240 7 280 The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation. A. 1/40 dollars per room; the cost is $40 for each person. B. 40/1 dollars per person; the cost is $40 for each person. C. 1/280 dollars per person; the cost is $1 for 280 people. D. 160/1 dollars per person; the cost is $160 for each person.
The answer is B. 40/1 dollars per person; the cost is $40 for each person.
At a wedding reception, the bride and groom and five attendants will form a receiving line. How many ways can they be arranged in each of following cases? a) Any order will do. b) The bride and groom must be the last two in line. c) The groom must be last in line with the bride next to him.
A. In this case, they can be arranged at any order. Since there are 7 people all in all, therefore the number of arrangements is:
number of arrangements = 7P7 = 5040 ways
B. In this case, only the 5 people can be arranged in any order therefore 5P5. However the groom and bride can be interchanged on 2 places, therefore:
number of arrangements = 5P5 * 2 = 240 ways
C. In this case, only the 5 people can be arranged in any order while the groom and bride can no longer be interchanged, therefore:
number of arrangements = 5P5 = 120 ways
Final answer:
The arrangements for the wedding reception receiving line can be calculated using permutations: a) Any order will do, giving 7!, b) The bride and groom must be the last two in line, giving 5!, c) The groom must be last in line with the bride next to him, giving 6! x 2.
Explanation:
The question asks about the number of ways a bride and groom along with five attendants can be arranged in a receiving line at a wedding reception under different conditions. This is a permutations problem where we calculate the arrangements using factorial notation.
Case a: Any order will do.
In this case, we have a total of 7 people (bride, groom, and five attendants) who can be arranged in any order. The number of arrangements is the factorial of 7, which is calculated as 7! (7 factorial). So, the number of ways they can be arranged is 7! (which is 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5,040 ways).
Case b: The bride and groom must be the last two in line.
Since the bride and groom's positions are fixed at the end of the line, we only need to arrange the five attendants. This is equivalent to 5! arrangements for the attendants. Thus, the number of ways they can be arranged is 5! (which is 5 x 4 x 3 x 2 x 1 = 120 ways).
Case c: The groom must be last in line with the bride next to him.
Here, the bride and groom are fixed in the last two positions, but the bride must be next to the groom. We consider the bride and groom as a single unit in addition to the five attendants. This gives us 6! arrangements for the attendants and the bride-groom unit, multiplied by 2 because the bride and groom can switch places within their unit. So, the number of ways they can be arranged is 6! x 2 (which is 6 x 5 x 4 x 3 x 2 x 1 x 2 = 1,440 ways).