$35,485.00 to $50,606.00 per year is equivalent to how much an hour

Answers

Answer 1

assuming it is based on a 40 hour work week, working 52 weeks per year:

35485/52 = 682.40 per week

682.40/40 = 17.06 per hour

50606/52 = 973.19 per week

973.19/40 = 24.33 per hour

 so between 17.06 & 24.33 per hour


Related Questions

are all semi circles simular

Answers

technically speaking, yes, but the size would be different for some

A car travels at an average speed of 52 miles per hour. how many miles does it travel in 3 hours and 30 minutes?

Answers

The answer will be 52*3 + 52*1/2 = 156 + 26 = 182 miles

2x − y = 3 4x = 6 + 2y

Answers

We want to solve
2x - y = 3
4x = 6 + 2y

The second equation, after diving through by 2, is
2x = 3 + y
or
2x - y = 3

The system of equations is
2x - y = 3          (1)
2x - y = 3          (2)

These two equations are identical, so we actually have only one equation for determining x and y.
That is,
y = 2x - 3

For any real value of x, there will be a corresponding value of y.
Therefore there an infinite number of solutions, and no unique solution exists.

Answer: There is no unique solution.

Find the three arithmetic means between 7 and 21

Answers

Since we are finding three arithmetic means between 7 and 21, that means there are 4 intervals between 7 and 21. The difference between 21 and 7 is 14, which we divide by 4 to get the value of each interval. Since each interval is 14/4 or 3.5, we keep adding that value to 7 to get our three arithmetic means. They are 10.5, 14, and 17.5

the base of an exponential function cannot be a negative number true or false

Answers

Answer:

True

Step-by-step explanation:

Given statement : The base of an exponential function cannot be a negative number.

We need to check whether the given statement is true or not.

The general form of an exponential function is

[tex]f(x)=ab^x[/tex]

where, a is the initial value and b is the base of exponential function.

The value of base b is always greater than 0 because

1. The terms like [tex](-3)^\frac{1}{2}[/tex] is an imaginary number and it make no sense. So, the base of an exponential function cannot be a negative number.

2. It b=0, then [tex](0)^x=0[/tex], which is a constant function. So, the base of an exponential function cannot be 0.

It means b>0.

Therefore, the given the given statement is true.

Final answer:

The base of an exponential function must be positive, as a negative base can lead to undefined values when raised to non-integer exponents. The rate of growth of an exponential function with a positive base near one can be approximated by 1+x for small x. Bases for exponential functions can often be connected to Euler's number e (approximately 2.71818).

Explanation:

The statement that the base of an exponential function cannot be a negative number is true. The base of an exponential function needs to be positive because a negative base can lead to undefined or complex values when raised to a fractional or irrational exponent. For example, the exponential function with base e (where e is the Euler's number, approximately equal to 2.71818) demonstrates natural growth, and its rate of growth for small x values approximates to 1+x. This approximation indicates how for a small change in x, the change in the value of the function is nearly proportional when the base is a positive number close to one.

Considering other bases, they can be related to base e using the identity ax = eln(a)x, where a is a positive real number, and ln(a) is the natural logarithm of a. Thus, whether for common or natural bases, the exponential function is well-defined only for positive bases.

How do units help you to better understand a problem? How do units sometimes get in the way of solving a problem?

Answers

Unit of measurement is a standard for measurement of a quantity. Every quantity has its own units. The system is called  International System of Units. But, units also help us to better understand a problem. With units we can represent the meaning of the problem and the effect that if a certain event occurs. So, we units we can in a certain way measure the problem. On the other hand, units can sometimes get in the way of solving a problem because it can make confusion and can not measure human impact and influence, because are irrational and unpredictable. 

factors of 3x^2y^2+6x^2+12y^2+24

Answers

look for  the GCF

GCF = 3

so we have 

3 (x^2y^2 + 2x^2 + 4y^2 + 8)      Factor by grouping:-

= 3[ x^2(y^2 + 2) + 4(y^2 + 2)]

= 3(x^2 + 4)(y^2 + 2)

If you multiply me by 3 and increase that value by 3 I am 20. What's my number?

Answers

Use x for the unknown value.
Multiply by three: 3x.
Increase that value by 3: 3x +  3

Write an equation: 3x + 3 = 20.
Use the order of operations to solve.
3x + 3 = 20
3x = 17
x = 17/3

The unknown value would be 17/3.
The number is 5.666667.  You can redo the steps using these inverse operations: 20-3=17, then 17/3 to get 5.666667.

Does arkansas lie south of 40 degrees latitude

Answers

All of Arkansas is between 33 degrees and 36.5 degrees lol

Oil is poured on a flat surface and it spreads out forming a circle. the area of this circle is increasing at a constant rate of 10⁡cm2/s. determine the rate of change of the radius of the circle when the radius is 10⁡cm

Answers

yay


derivitives

everything is taken derivitve in repsect to time

da/dt=10cm^2/s

alright
area=pir^2
da/dt=2pir dr/dt
10cm^2/s=2pir dr/dt
r=10
[tex]\frac{10cm^2}{sec}=2\pi 10cm\frac{dr}{dt}[/tex]
[tex]\frac{10cm^2}{sec}=20\pi cm \frac{dr}{dt}[/tex]
divide both sides by 20pi
[tex]\frac{10cm^2}{20cm \pi sec}= \frac{dr}{dt}[/tex]
[tex]\frac{1cm}{2\pi sec}= \frac{dr}{dt}[/tex]

the rate of change of the radius when radius=10 is [tex]\frac{1cm}{2\pi sec}[/tex]

The rate of change of radius of the circle when the radius is 10 cm is

dr / dt = 1/2π cm / sec

What is implicit differentiation?

In mathematics, differentiation is the process of determining the derivative, or rate of change, of a function. Differentiation is a technique for determining a function's derivative. Differentiation is a mathematical procedure that determines the instantaneous rate of change of a function based on one of its variables. The process of finding the derivative of dependent variable in an implicit function by differentiating each term separately

Given data ,

Oil is poured on a flat surface and it spreads out forming a circle

The area of the circle is increasing at a rate of 10 cm²/sec

Let the area of the circle be = A

So , the equation is dA² / dt² =  10 cm²/sec

The area of the circle = πr²

So , dA² / dt² = 2π dr / dt

2πr dr / dt = 10 cm²/sec

Substituting the value of r in the equation , we get

2π x 10 dr / dt = 10 cm²/sec

20π dr / dt = 10 cm²/sec

Divide both sides of the equation be 20π

dr / dt = ( 1/2π ) cm / sec

Therefore , the rate of change of radius of the circle is ( 1/2π ) cm / sec

Hence , The rate of change of radius of the circle when the radius is 10 cm is dr / dt = 1/2π cm / sec

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How many real solutions does the equation: x2-7x+10=0 have?

Answers

The discriminant is 9 and since the discriminant is a positive number, there are two real solutions to the equation. 

What is 10(x+7) if x=6 ?

Answers

10 (x + 7) - 17 ; x = 6
Substitute 6 for x, rewrite the equation:
10 (6 + 7) - 17
PEMDAS
Parentheses -> Exponents -> Multiplication/Division -> Addition/Subtraction
10 (13) - 17
130 - 17
113
[tex]\displaystyle \text{The problem is:\ 10(x + 7) - 17=? if x=6} \\ \\ \text{So, firstly replace x with 6 :)} \\ \\ \text{New equation is: 10(6+7)-17=?} \\ \\ \text{Bon, now, we calculate the parenthesis} \\ \\ 10 \cdot13-17=? \\ \\ \text{Order of operation, firstly multiply.} \\ \\ 130-17=? \\ \\ \text{Now, all is clear } \\ \\ 130-17= \boxed{ \boxed{\bold{113}}}[/tex]

A local supermarket sells chicken fir $2.49/lb and pork for $3.19/lb.Todd buys "c" pounds of chicken and "p" pounds ofpork which of the following inequalities represents that Todd only has $40 to spend?

Answers

since is buying both pork and chicken, it would be D since it adds both priced together

How much would $125 invested at 8% interest compounded continuously be worth after 16 years? Round your answer to the nearest cent. Do not include units in your answer.

Answers

The formula is
A=p e^rt
A future value?
P present value 125
E constant
R interest rate 0.08
T time 16 years
A=125×e^(0.08×16)
A=449.58 round your answer to get
A=450

solve the following equation -2x + 4 = 2 (4x - 3) -3 (-8 + 4x)
a.7
b.2
c.-7
d.3

Answers

it would be B I think

Answer:

[tex]A) 7[/tex]

Step-by-step explanation:

[tex]-2x+4=2\left(4x-3\right)-3\left(-8+4x\right)[/tex]

[tex]2\left(4x-3\right)-3\left(-8+4x\right)[/tex]

[tex]2 (4x - 3)[/tex]

[tex]\longrightarrow8x-6[/tex]

[tex]\longrightarrow 8x-6-3\left(-8+4x\right)[/tex]

[tex]-3 (-8 + 4x)[/tex]

[tex]\longrightarrow 24-12x[/tex]

[tex]8x-6+24-12x[/tex]

Combine like terms:

[tex]8x-12x-6+24[/tex]

Add: [tex]8x-12x=-4x[/tex]

Add: [tex]-6+24=18[/tex]

[tex]\longrightarrow-2x+4=-4x+18[/tex]

Subtract 4 from both sides:

[tex]\longrightarrow-2x+4-4=-4x+18-4[/tex]

[tex]\longrightarrow-2x=-4x+14[/tex]

Add 4x to both sides:

[tex]\longrightarrow-2x+4x=-4x+14+4x[/tex]

[tex]\longrightarrow2x=14[/tex]

Divide both sides by 2:

[tex]\longrightarrow\frac{2x}{2}=\frac{14}{2}[/tex]

[tex]\longrightarrow x=7[/tex]

____________________________

OAmalOHopeO

-2(4g-3)= 30 how do i solve this

Answers

-2(4g-3)= 30
-8g+6= 30
-8g=30-6
-8g= 24
G= 24/-8
G= -3

Hope this helps!

distributive property
-2(4g-3)=30
-8g+6=30
-8g=24


g= -3
Hope this helped!

A rectangular yard measuring 41ft by 60ft is bordered (and surrounded) by a fence. Inside, a walk that is 4ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.

Anyone wanna help? I'd really appreciate it.

Answers

area of yard = 41 x 60 = 2460 square feet

walk is 4 feet wide

 41-4 =37, 60-4 = 56

37*56 = 2072

2460-2072 = 388

 area of walk is 388 square feet

WILL GIVE BRAINLIEST PLEASE HELP!!!

Which of the following equals 1/16 when evaluating f (–2)?

A.
f(x)=2^(x-2)
B.
f(x)=-2^(x-6)
C.
f(x)=-2^(n-2)
D.
f(x)=2^(n-8)

Answers


f(x)=2^(x-2) = 2^(-4) = 1/2^4  = 1/16

answer
A.
f(x)=2^(x-2)

Nancy is a telemarketer who calls 96 people each day. How many people will she call in a 5-day workweek?

A. 430
B. 460
C. 480
D. 380

Answers

96 * 5  = 480 people

Its C
Answer is C. 480 because 96 x 5 = 480

what is 1,627,187 rounded to the nearest ten?

Answers

the answer is 1,627,190

Given the table below, determine if the data represents a linear or an exponential function and find a possible formula for the function.

(x): 0, 1, 2, 3, 4
f(x): 14, 12.6, 11.34, 10.206, 9.185

A) Exponential; y=14(0.10)^x
B) Linear; y= -1.2024x + 13.871
C) Exponential; y= 14(0.90)^x
D) Linear; 18.871x - 1.2024

Please explain you answer. Please someone help me, I'm in need of some help.

Answers

The answer is C) y=14(0.9)ˣ and it's an exponential function

PROOF 

Give to x the respective values of x & calculate y, using y = 14(0.9)ˣ

x         |       y
---------|---------
0         | 14(0.9)⁰ = 14
1         | 14(0.9)¹ = 12.6
2         | 14(0.9)² = 11.34
3         | 14(0.9)³ = 10.206
4         | 14(09)⁴ =  9.1845

Answer:

simplified answer: its letter c

Step-by-step explanation:

Which of the following is the number 0.008005 written in scientific notation?
A. 8.005 x 10(squared)
B. 8.500 x 10(to the negative third power)
C. 8.005 x 10(to the negative fourth power)
D. 8.005 x 10(to the negative third power

Answers

A. 8.005 • 10² = 800.5 (Incorrect)

B. 8.500 • 10⁻³ = 0.0085 (Incorrect)

C. 8.005 • 10⁻⁴ = 0.000801 (Incorrect)

D. 8.005 • 10⁻³ = 0.008005 (Correct)

Answer: D. 8.005 • 10⁻³

Give an equation for a horizontal line and a vertical line. what are the slopes of each line

Answers

A horizontal line has a slope of 0. Remember the z in horizontal means zero. The slope of a vertical line is undefined.

Answer:

1 + 1 = 2

2 - 1 = 1

The line's slopes are cute

Step-by-step explanation:

I hope your lines enjoy their equations, you are a great parent to your lines. =D

If y=m^4=n^3 and y is greater than 1, then mn=

Answers

Final answer:

If we equate the two given equations y = m^4 and y = n^3, we can express mn as m^(7/3) or as n^(7/4). This is done by taking the cube root and square root on both sides of the equated equation to isolate m and n.

Explanation:

If we have two equations, y = m^4 and y = n^3, where y > 1, we can equate these two equations since they are both equal to same value 'y'. So the equation will be m^4 = n^3. To find the value of mn, we want to express it in terms of 'y'. So we take cube root on both sides, it will be m = (n^3)^(1/4) = n^(3/4). And square root on both sides will give n = (m^4)^(1/3) = m^(4/3). Now mn = m * m^(4/3) = m^(1 + 4/3) = m^(7/3). Similarly, mn = n * n^(3/4) = n^(1 + 3/4) = n^(7/4). Hence, mn can be expressed either as m^(7/3) or n^(7/4).

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Find the derivative of f(x) = 8 divided by x at x = -1.
A. 4
B. 0
C. 8
D. -8

Answers

If f(x)=8/x it means f'(x) = -8/x^2
f'(x) -> derivative
so f'(-1) will be -8/1=-8
The answer is D

The derivative of f(x) at x = -1 is -8.

What is a derivative?

Derivative is the rate of change of a function with respect to a variable. Derivatives are fundamental to the solution of problems in calculus and differential equations.

According to the given problem,

f(x) = [tex]\frac{8}{x}[/tex]

Derivative of f(x),

⇒ f'(x) = [tex]-\frac{8}{x^{2} }[/tex]

At x = -1,

⇒ f'(-1) =  [tex]-\frac{8}{(-1)^{2} }[/tex]

          = -8

Hence, we can conclude, the derivative of f(x) at x = -1 is -8.

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Solve for F. Let m=5, a=3 F=ma

Answers

The answer will be: F= 5*3 = 15

Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother. Charlie has $27. How much can he spend on each sandwich if they are all the same price? Choose two answers: one for the inequality that models this situation and one for the correct answer. A. Inequality: 3x + 6 < 27 B. Inequality: 6x + 3 ≤ 27 C. Inequality: 6x + 3 ≥ 27 D. Inequality: 3x + 6 ≥ 27 E. Answer: $7 or less F. Answer: $4 or less

Answers

B. because 6 x 4 = 24 + 3 = 27 and that is _< to 27 and F.

Answer-

The inequality that models this situation is,

[tex]\boxed{\boxed{B.\ 6x+3\leq 27}}[/tex]

Solution-

The total money Charlie has = $27

He wants to order 6 sandwiches and a kid's meal of $3

Let us assume the price of each sandwiches is x.

So, the amount he will be spending for sandwiches is $6x

The total amount he will be spending is $(6x+3)

As he has only $27, so he can spend any amount less than or equal to 27

So the inequality becomes,

[tex]\Rightarrow 6x+3\leq 27[/tex]

Therefore, the inequality that models this situation is [tex]6x+3\leq 27[/tex]

If x2 + xy + y3 = 1, find the value of y''' at the point where x = 1.

Answers

The third derivative of the function is [tex]y^{'''}=\dfrac{\left(3y^2+12xy-x\right)y''+y'\left(6yy'+12xy'+12y-1\right)-\left(6y-1\right)y'-6yy'}{\left(3y^2+x\right)^2}-\dfrac{2\left(6yy'+1\right)\left(\left(3y^2+12xy-x\right)y'-y\cdot\left(6y-1\right)\right)}{\left(3y^2+x\right)^3}[/tex]and the value at the point x = 1 is 42

How to determine the third derivative at the point x = 1

From the question, we have the following parameters that can be used in our computation:

[tex]x^2 + xy + y^3 = 1[/tex]

Differentiate implicitly

So, we have

[tex]3y^2y' + xy'+y+2x=0[/tex]

Make y' the subject of formula

So, we get

[tex]y'=-\dfrac{y+2x}{3y^2+x}[/tex]

Differentiate the second time

Using a graphing tool, we have

[tex]y''=\dfrac{\left(3y^2+12xy-x\right)y'-6y^2+y}{\left(3y^2+x\right)^2}[/tex]

Differentiate the third time to get the third derivative

Using a graphing tool, we have

[tex]y^{'''}=\dfrac{\left(3y^2+12xy-x\right)y''+y'\left(6yy'+12xy'+12y-1\right)-\left(6y-1\right)y'-6yy'}{\left(3y^2+x\right)^2}-\dfrac{2\left(6yy'+1\right)\left(\left(3y^2+12xy-x\right)y'-y\cdot\left(6y-1\right)\right)}{\left(3y^2+x\right)^3}[/tex]

Recall that

x = 1

Calculating y, we have

[tex]1^2 + (1)y + y^3 = 1[/tex]

[tex]1 + y + y^3 = 1[/tex]

[tex]y^3 + y = 0[/tex]

Factorize

[tex]y(y^2 + 1) = 0[/tex]

So, we have

y = 0 or [tex]y^2 + 1 = 0[/tex]

The equation [tex]y^2 + 1 = 0[/tex] will give a complex solution

So, we have

x = 1 and y = 0

Calculating y', we have

[tex]y'=-\dfrac{0+2(1)}{3 * 0^2+1}[/tex]

[tex]y'=-\dfrac{2}{1}[/tex]

y' = -2


Calculating y", we have

[tex]y''=\dfrac{\left(3y^2+12y-1\right)y'-6y^2+y}{\left(3y^2+1\right)^2}[/tex]

[tex]y''=\dfrac{\left(3(0)^2+12(1)(0)-1\right)(-2)-6(0)^2+0}{\left(3(0)^2+1\right)^2}[/tex]

[tex]y''=\dfrac{\left2}{1}[/tex]

y" = 2

Calculating y", we have

[tex]y^{'''}=\dfrac{\left(3y^2+12xy-x\right)y''+y'\left(6yy'+12xy'+12y-1\right)-\left(6y-1\right)y'-6yy'}{\left(3y^2+x\right)^2}-\dfrac{2\left(6yy'+1\right)\left(\left(3y^2+12xy-x\right)y'-y\cdot\left(6y-1\right)\right)}{\left(3y^2+x\right)^3}[/tex]

Simplifying the denominators, we have

[tex](3y^2 + x)^2 = (3(0)^2 + 1)^2 = 1[/tex]

[tex](3y^2 + x)^3 = (3(0)^2 + 1)^3 = 1[/tex]

So, we have

[tex]y^{'''}=\dfrac{\left(3y^2+12xy-x\right)y''+y'\left(6yy'+12xy'+12y-1\right)-\left(6y-1\right)y'-6yy'}{1}-\dfrac{2\left(6yy'+1\right)\left(\left(3y^2+12xy-x\right)y'-y\cdot\left(6y-1\right)\right)}{1}[/tex]

Divide

[tex]y^{'''}=[\left(3y^2+12xy-x\right)y''+y'\left(6yy'+12xy'+12y-1\right)-\left(6y-1\right)y'-6yy']-[2\left(6yy'+1\right)\left(\left(3y^2+12xy-x\right)y'-y\cdot\left(6y-1\right)\right)][/tex]

Simplifying each term:

[tex](3y^2+12xy-x)y''+y'(6yy'+12xy'+12y-1)-(6y-1)y'-6yy' = (3(0)^2+12(1)(0)-(1))(2) + (-2)(6(0)(-2) +12(1)(-2) + 12(0) - 1) - (6(0) - 1)(-2) - 6(0)(-2)[/tex]

[tex](3y^2+12xy-x)y''+y'(6yy'+12xy'+12y-1)-(6y-1)y'-6yy' = 46[/tex]

Also, we have

[tex]2(6yy'+1)((3y^2+12xy-x)y'-y(6y-1)) = 2(6(0)(-2) + 1)((3(0)^2 + 12(1)(0) - 1)(-2) - 0(6(0)-1))[/tex]

[tex]2(6yy'+1)((3y^2+12xy-x)y'-y(6y-1)) = 4[/tex]

So, the expression becomes (by substitution)

[tex]y^{'''}= 46 -4[/tex]

This gives

[tex]y^{'''}= 42[/tex]

Hence, the third derivative at the point x = 1 is 42

Which of the following are vertical asymptotes of the function y = 2cot(3x) + 4? Check all that apply. A.x = pi/3 B.x = +/- pi/2 C.x = 2pi D.x = 0

Answers

The vertical asymptotes of the function y = 2cot(3x) + 4 are  A.x = π/3  C. x = 2π D.x = 0

How to determine the vertical asymptote?

The function is given as:

y = 2cot(3x) + 4

The above function is a cotangent function, represented as:

y = Acot(Bx +C) + D

By comparison, we have:

B = 3

The vertical asymptotes are then calculated using:

[tex]x = \frac{\pi}{B}n[/tex], where n are integers

Substitute 3 for B

[tex]x = \frac{\pi}{3}n[/tex]

Using the above format, the vertical asymptotes in the options are  A.x = π/3  C. x = 2π D.x = 0

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To win a state "A" lottery, one must correctly select 5 numbers from a collection of 50 numbers (1 through 50). The order in which the selection is made does not matter. The neighboring state "B" has a lottery where one must correctly select 6 numbers from a collection of 60. Which lottery would you rather play? Support your choice with mathematical calculations.

Answers

The number of possibilities for the first one is 50 choose 5, and the number of possibilities for the second one is 60 choose 6. Since 50 choose 5 is 2118760 and 60 choose 6 is 50063860. There are less possible outcomes for state "A" and therefore you have a higher chance of winning.
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