(08.02)How many solutions are there for the system of equations shown on the graph?
No solution
One solution
Two solutions
Infinitely many solutions

(08.02)How Many Solutions Are There For The System Of Equations Shown On The Graph? No Solution One Solution

Answers

Answer 1
There is no solution since the lines never intersect.
Answer 2

Answer:

The system of equations has no solution

Step-by-step explanation:

We have to find the number of solutions of system of equations shown in the graph.

Since, the number of solutions of system of equations is that point of thew graph on which the graph of two equations meet.

Since, we can see from the graph the two lines are parallel

Hence, they can never meet.

Hence, the system of equations has no solution.

Hence, first option is correct.


Related Questions

100 POINTS!!!! Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table for at least four values for the function. Remember to include the two points of intersection in your table. Can you just give me the X and Y values? 

Answers

Based on the docx you showed me, the equation for the parabola is [tex]y = x^2 + 36[/tex] and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).

If you use these two points to create a line we get the equation:

[tex]y - 6 = \frac{34 - 6}{-2 - 5}(x - 5)[/tex] (I just used point slope form)

This can be simplified to:

[tex]y = \frac{40}{-7}x + \frac{242}{7}[/tex]

Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept: [tex](0, \frac{242}{7})[/tex] and the x-intercept: [tex](\frac{121}{20}, 0)[/tex].

So our table of value can be:

x          | y
______|________
-2         | 34
0          | 242 / 7
5          | 6
121/20 | 0

In spherical geometry, which indicates the possible number of right angles a triangle may have?
1
2
3
All of the above

Answers

In planar geometry, we know that the sum of all angles of a triangle is exactly 180°, However, in spherical geometry, different rules apply. When three arcs drawn on the surface of the sphere are connected together through vertices, that is called a spherical triangle. In that case, the sum of all three angles of a spherical triangle is between 180° and 540°.

So, if a triangle has one 90° angle, there are still excess angles to make up for a maximum of 540°. The same is true for two 90° angles. You would exceed 180° but that is just the lower limit so that is still acceptable. If you have three 90° angles, you form a spherical triangle with a total of 270°, which is within the given range. Thus, the answer is all of the above.

Which of the following is an extraneous solution of sqrt(-3x-2)=x+2 a.-6 b.-1 c.1 d.6

Answers

try plugging in the 4 solutions and see if they fit
for example a, x - 6 is not extraneous  because  

left side = sqrt (-3*-6 - 2) == sqrt16 = 4 or -4
right side = -6 + 2 = -4

so x = -6 is not extraneous

Answer:

- 6 is the extraneous solution.

Step-by-step explanation:

Given : [tex]\sqrt{-3x -2} = x + 2[/tex].

To find : Which of the following is an extraneous solution .

Solution : We have given that [tex]\sqrt{-3x -2} = x + 2[/tex].

Taking square both sides

-3x - 2 = [tex](x+2)^{2}[/tex].

On applying identity  [tex](a+b)^{2}[/tex] = a² + b² + 2ab

Then ,

-3x -2 =  x² + 2² + 2 * 2 *x

-3x -2 =  x² + 4 + 4x.

On adding both sides by 3x

-2 =  x² + 4 + 4x + 3x

-2 =  x² + 4 + 7x

On adding both sides by 2

0 =  x² + 4 + 7x + 2

On switching sides

x² +7x + 6 = 0

On Factoring

x² +6x + x + 6 = 0

x ( x+ 6 ) +1 (x +6 ) = 0

On grouping

( x +1) ( x +6) = 0

x = -1, -6.

Let check for x = -6

[tex]\sqrt{-3 (-6) -2} = -6 + 2[/tex].

4 =  -4

An extraneous solution is a root of a transformed equation that is not a root of the original equation.

Therefore,  -6 is the extraneous solution.

(a) a pizza parlor has a choice of 11 toppings for its pizzas. from these 11 toppings, how many different 7 -topping pizzas are possible?

Answers

To solve for the number of different possible pizzas with 7 toppings out of 11 and the arrangement of these toppings is not important, therefore we use the combination formula.

The formula for combination is:

n C r = n! / r! (n – r)!

where,

n = is the total number of toppings = 11

r = the number of toppings in a pizza = 7

Substituting the values into the equation:

11 C 7 = 11! / 7! (11 – 7)!

11 C 7 = 11! / 7! * 4!

11 C 7 = 330

 

Therefore there are a total different 330 pizzas with 7 different combinations toppings.

Final answer:

330 different combinations.

Explanation:

The student's question is about combinations in Mathematics, specifically how many 7-topping pizzas can be made from a choice of 11 toppings. This is a combinatorics problem, and the solution involves the use of the combination formula, which is given as:

C(n, k) = n! / (k!(n-k)!)

where n is the total number of items to choose from, k is the number of items to choose, n! denotes the factorial of n, and C(n, k) represents the number of combinations.

In this case, n is 11 (the total number of toppings) and k is 7 (the number of toppings on the pizza).

Therefore, the number of different 7-topping pizzas possible is:

C(11, 7) = 11! / (7!(11-7)!) = 11! / (7!4!) = (11x10x9x8)/(4x3x2x1) = 330

Hence, 330 different 7-topping pizzas are possible.

Find the value tan 39 degrees. Round to the nearest ten-thousandth

A ) 0.8098
B ) 0.6293
C ) 0.7771
D ) 3.6146

Answers

You can do this using a scientific calculator

mine gives tan 39  =  0.8097840332

which is 0.8098 to nearest ten thousandth.

Which of the following is an arithmetic sequence?
a -7/11,6/11, -5/11, 4/11
b -3/4, -3/5, -3/6, -3/7
c 1/2,2,7/2,5
d 3/4,-3/2, 3, -6

Answers

I think it's D, because 3/4 x 2 = - 3/2
and then - 3/2 x - 2 = 3
3 x - 2 = - 6

Hope that helps <3

The sequence 3/4,-3/2, 3, -6 is the arithmetic sequence.

Common difference

The difference between two successive terms of an arithmetic progression is known as a common difference.

How to check the common difference?

(a)

We will find the common difference between each term of the given sequences by subtracting a term and its previous term.

[tex](\frac{6}{11}- \frac{-7}{11}) \neq (\frac{-5}{11} -\frac{6}{11} )\neq (\frac{4}{11} -\frac{-5}{11})[/tex]

[tex]\frac{13}{11}\neq \frac{-11}{11}\neq \frac{9}{11}[/tex]

So, option (a) is incorrect.

(b)

We will take the common difference between the terms.

[tex](\frac{-3}{5} -\frac{-3}{4} )\neq (\frac{-3}{6} -\frac{-3}{5} )\neq (\frac{-3}{7} -\frac{-3}{6} )\\[/tex]

[tex]\frac{3}{20} \neq \frac{3}{30}\neq \frac{3}{42}[/tex]

So, option (b) is also incorrect.

(c)

We will take the common difference between the terms.

[tex](2-\frac{1}{2} )= ( \frac{7}{2}-2 )= (5 - \frac{7}{2} )[/tex]

[tex]\frac{3}{2}= \frac{3}{2} = \frac{3}{2}[/tex]

Since the difference between the terms is common.

Thus, option (c) is correct.

(d)

We will take the common difference between the terms.

[tex](\frac{-3}{2}- \frac{3}{4})\neq (3-\frac{3}{2})\neq (-6-3)[/tex]

[tex]\frac{-18}{2}\neq \frac{9}{2}\neq (-9)[/tex]

So, option (d) is incorrect.

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The depth of the water at the end of a pier changes periodically along with the movement of tides. On a particular day, low tides occur at 12:00 am and 12:30 pm, with a depth of 2.5 m, while high tides occur at 6:15 am and 6:45 pm, with a depth of 5.5 m. Let t = 0 be 12:00 am. Which periodic function, sine or cosine, would be a simpler model for the situation? Explain.

Answers

Answer: A cosine function would be a simpler model for the situation.

The minimum depth (low tide) occurs at

t = 0. A reflection of the cosine curve also has a minimum at t = 0.

A sine model would require a phase shift, while a cosine model does not.

Step-by-step explanation:

Using a cosine function is simpler to model the tide changes because it starts at the maximum value, aligning with the high tide occurrence.

The depth of the water at the end of a pier changes periodically due to tides. Given that low tides occur at 12:00 am and 12:30 pm with a depth of 2.5 m, and high tides occur at 6:15 am and 6:45 pm with a depth of 5.5 m, we need to model this situation with a periodic function.

Let's align this with a cosine function for simplicity. In general, the cosine function can be modeled as y = A cos(B(t - C)) + D, where:

A is the amplitude (half of the difference between high tide and low tide depth, (5.5 m - 2.5 m)/2 = 1.5 m)B determines the period (a full tide cycle is roughly 12 hours and 25 minutes or 747.5 minutes; B = 2π/747.5)C is the horizontal shift (shift corresponding to the time of the first high tide, 6.25 hours or 375 minutes, so C = 375)D is the midline of the function (average depth, (5.5 m + 2.5 m)/2 = 4 m)

Therefore, the function becomes: y(t) = 1.5 cos((2π/747.5)(t - 375)) + 4. Using a cosine function is simpler because it starts at the maximum value, which corresponds to the high tide.

What number should be added to both sides of the equation to complete the square? x^2 â 10x = 7?

Answers

You should add 25 because you should always add the square of the p value (which is equal to half of the b value, which makes the p value 5).
Basically, the p value should be half of b and the square root of c.

Solve x 2 + 9x + 8 = 0 by completing the square. What are the solutions?

Answers

x^2+9x+8=0

 (x+1)(x+8)=0

x+1=0

x=-1

x+8 = 0

x=-8


 solutions are -1 and -8

Five members of the soccer team and five members of the track team ran the 100-meter dash. Their times are listed in the table below: Soccer Track 12.3 12.3 13.2 11.2 12.5 11.7 11.3 12.2 14.4 13.7 What is the difference of the means for the two groups? 0.52 12.22 12.74 24.96

Answers

soccer : (12.3 + 13.2 + 12.5 + 11.3 + 14.4) / 5 = 63.7 / 5 = 12.74
track : (12.3 + 11.2 + 11.7 + 12.2 + 13.7) / 5 = 61.1 / 5 = 12.22

difference is : 12.74 - 12.22 = 0.52 <=

Answer:

Hence, the difference in Mean of two teams is:

0.52

Step-by-step explanation:

Five members of the soccer team and five members of the track team ran the 100-meter dash.

Their time is listed as:

Soccer          Track

   12.3              12.3

   13.2               11.2

   12.5               11.7

   11.3                12.2

    14.4               13.7

The mean of the soccer team is given by:

[tex]Mean_1=\dfrac{12.3+13.2+12.5+11.3+14.4}{5}\\\\Mean_1=12.74[/tex]

The mean of track team is given by:

[tex]Mean_2=\dfrac{12.3+11.2+11.7+12.2+13.7}{5}\\\\Mean_2=\dfrac{61.1}{5}\\\\Mean_2=12.22[/tex]

Hence, the Difference in Mean is:

[tex]Mean_1-Mean_2\\\\=12.74-12.22\\\\=0.52[/tex]

Hence, the difference in Mean of two teams is:

0.52

Find H to the nearest degree.

Answers

sin(angle) = opposite/hypotenuse
sin(H) = GF/HF
sin(H) = 5/13
arcsin(sin(H)) = arcsin(5/13)
H = 22.61986 ... which is approximate
H = 23 degrees ... round to the nearest whole number

Answer is choice A

Dominique is thinking about buying a house. The table below shows the projected value of two different houses for three years.

House 1 (value in dollars) year 1: 286,000 year 2: 294,580 year 3: 303,417.40 House 2 (value in dollars) year 1: 286,000 year 2: 295,000 year 3: 304,000

Part A: What type of function, linear or exponential, can be used to describe the value of each of the houses after a fixed number of years? Explain your answer.

Part B: Write one function for each house to describe the value of the house f(x), in dollars, after x years.

Part C: Dominique wants to purchase a house that would have the greatest value in 25 years. Will there be any significant difference in the value of either house after 25 years? Explain your answer, and show the value of each house after 25 years.

Answers

Part C, since the equation is 286,000 x 3squared, then the house that would greatly increase in value in 25 years would be C.

The functions for House 1 and House 2 are [tex]\(f_1(x) = 5079.6x + 248900.4\)[/tex] and [tex]\(f_2(x) = 4666.\overline{66}x + 256000\)[/tex] respectively.

After 45 years, House 1 will be valued at $477,555, and House 2 will be valued at $465,000.

Here's the step-by-step solution with complete calculations for the given problem:

Part A: Identifying the Function Type

- House 1:

 - Year 1 to Year 2: [tex]\(259,059.60 - 253,980 = 5,079.60\)[/tex]

 - Year 2 to Year 3: [tex]\(264,240.79 - 259,059.60 = 5,181.19\)[/tex]

- House 2:

 - Year 1 to Year 2: [tex]\(263,000 - 256,000 = 7,000\)[/tex]

 - Year 2 to Year 3: [tex]\(270,000 - 263,000 = 7,000\)[/tex]

The functions are linear because the changes are constant for House 2 and almost constant for House 1.

Part B: Formulating the Equations

- House 1 Equation:

 - Slope (m): [tex]\(5079.6\)[/tex]

 - Y-intercept (c): [tex]\(248900.4\)[/tex]

 - Equation: [tex]\(f_1(x) = 5079.6x + 248900.4\)[/tex]

- House 2 Equation:

 - Slope (m): [tex]\(4666.\overline{66}\)[/tex]

 - Y-intercept (c): [tex]\(256000\)[/tex]

 - Equation: [tex]\(f_2(x) = 4666.\overline{66}x + 256000\)[/tex]

Part C: Calculating Future Values

- House 1 Value at Year 45:

[tex]- \(f_1(45) = 5079.6 \times 45 + 248900.4 = 477555\)[/tex]

- House 2 Value at Year 45:

[tex]- \(f_2(45) = 4666.\overline{66} \times 45 + 256000 = 465000\)[/tex]

These equations predict the values of the houses after 45 years based on the given data. House 1 will be valued at $477,555, and House 2 will be valued at $465,000.

Is the relation {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)} a function? Explain. Type your answer below

Answers

Yes this is a function. The reason why is because there are no repeated x values. Each x value leads to exactly one y value. Put another way, for any given input, there is EXACTLY ONE output.

If you had something like {(1,2),(4,5),(1,7)} then it wouldn't be a function since x = 1 repeats itself. In this example, x = 1 leads to more than one output.

 {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)}

As long as there are the same x-value does not have multiple y-value results, it will be a function. This data array doesn't contain any recurring x-values. Therefore, this is a function (in simple terms of speaking).

What is the distance between the points (22, 27) and (2, -10)? if necessary, round your answer to two decimal places.a. 57 units?

Answers

distance formula : sqrt (x2 - x1)^2 + (y2 - y1)^2
(22,27)....x1 = 22 and y1 = 27
(2,-10)....x2 = 2 and y2 = -10
now we sub
d = sqrt (2 - 22)^2 + (-10 -27)^2)
d = sqrt (-20^2) + (-37^2)
d = sqrt (400 + 1369)
d = sqrt 1769
d = 42.06 <==

Answer:

42.06

Step-by-step explanation:

Two points (22,27) and (2,-10)

using distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

So, distance between (22,27) and (2,-10) is D

[tex]D=\sqrt{(22-2)^2+(27-(-10))^2}[/tex]

[tex]D=\sqrt{(20)^2+(37)^2}[/tex]

[tex]D=\sqrt{400+1369}[/tex]

[tex]D=\sqrt{1769}[/tex]

[tex]D=42.059[/tex]

Round off two decimal place.

[tex]D=42.06[/tex]

Hence, The distance between the points is 42.06

find an ordered pair that is a solution to the equation x-4y=4

Answers

Ordered pairs that are solutions to the equation x-4y=4 is (4, 0) and (0, -1).

The given equation is x-4y=4.

We need to find an ordered pair that is a solution to the equation.

How to find the solution to an equation?

The solutions of linear equations are the points at which the lines or planes representing the linear equations intersect or meet each other. A solution set of a system of linear equations is the set of values to the variables of all possible solutions.

From the graph, we can observe that (4, 0) and (0, -1) are solutions.

Verification of the solution (4, 0):

4-4y=4

⇒-4y=0

⇒y=0

Verification of the solution (0, -1):

0-4y=4

⇒-4y=4

⇒y=-1

Therefore, ordered pairs that are solutions to the equation x-4y=4 is (4, 0) and (0, -1).

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Which ordered pair is a solution to the system of inequalities? y <3 and y >-x+5 ?
A. (6,1)
B. (2,1)
C. (3,0)
D. (-2,4)

PS. for the equation y>-x+5, the sign should be greater than or equal to. I just can't find the key on my phone (>)

Answers

It should be A 6,1 because 6 is the x-axis and 1 is the y-axis

Write a variable expression for 9 more than a number s.

Answers

s+9

More than suggests addition.

59:26 What is the length of the hypotenuse, x, if (20, 21, x) is a Pythagorean triple? 22 29 41 42

Answers

if the legs are length a and b and hyptonuse is c then
a²+b²=c²

so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x

Answer:  the correct option is (B) 29.

Step-by-step explanation:  We are given to find the length of the hypotenuse x, if (20, 21, x) is a Pythagorean triple.

We know that

in a right-angled triangle, the lengths of the sides (hypotenuse, perpendicular, base) is a Pythagorean triple, where

[tex]Hypotenuse^2=Perpendicular^2+base^2.[/tex]

So,  for the given Pythagorean triple, we have

[tex]x^2=20^2+21^2\\\\\Rightarrow x^2=400+441\\\\\Rightarrow x^2=841\\\\\Rightarrow x=\sqrt{841}~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm29.[/tex]

Since the length of the hypotenuse cannot be negative, so x = 29.

Thus, the length of the hypotenuse, x = 29.

Option (B) is CORRECT.

At the movie theatre, child admission is $6.20 and adult admission is $9.80 . On Monday, twice as many adult tickets as child tickets were sold, for a total sales of $593.40 . How many child tickets were sold that day?

Answers

x= child

2x = adult


6.20x +9.80(2x) =593.40

6.20x +19.6x=593.40

25.80x =593.40

x=593.40/25.80 = 23

 23 childrens tickets were sold


Simplify fraction 23076923076923/10000000000000

Answers

so look what u going to do is to divide the fractions and u will get 2.3076923077 and that should be right

identify the maximum and minimum values of the function y = 3 cos x in the interval [-2π, 2π]. Use your understanding of transformations, not your graphing calculator.

Answers

The "vanilla" y=cos(x) function oscillates between -1 and +1. In the given function, only a multiplication with 3 is applied. The min and max scale accordingly, so the maximum becomes +3 and the minimum -3.

The x interval of [-2π, 2π] ensures that all y values are enclosed; the cosine makes two full sweeps.

The maximum value of the function y = 3 cos x will be 3.

The minimum value of the function y = 3 cos x will be - 3.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The function is,

⇒ y = 3 cos x

In the interval [-2π, 2π].

Now,

Since, The function is,

⇒ y = 3 cos x

Hence, We get;

The maximum value of the function y = 3 cos x is,

⇒ y = 3 cos2π

⇒ y = 3 × 1

⇒ y = 3

And, The minimum value of the function y = 3 cos x is,

⇒ y = 3 cos(-2π)

⇒ y = 3 × - 1

⇒ y = - 3

Thus, The maximum value of the function = 3.

The minimum value of the function = - 3.

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find the x intercepts of the parabola with vertex (2,13) and y-intercept (0,5) write your answer in this form: (x1,y1),(x2,y2) if necessary, round to the nearest hundredth

Answers

The standard formula for a parabola are

(x-h)^2 = +/- 4a (y-k) or (y-k)^2 = +/- 4a(x-h)

where
(h,k) is the coordinates of the vertex
a is the length of the focus from the vertes
+4a if the parabola opens upwards or to the right
-4a if the parabola opens downwards or to the left

The vertex (2,13) is situated in the 1st quadrant of the Cartesian plane. It only has y-intercept. This means that it only passes the y-axis once. Therefore, the parabola must open downwards and it passes the x-axis twice. The intersections at the x-axis are the x-intercepts. If the parabola has 2 x-intercepts, then the equation would be (x-h)^2 = -4a(y-k).

Let's use the y-intercept (0,5) to determine 4a:

(0-2)^2=-4a(5-13)
4a = 0.5

Therefore, the equation of the parabola is (x-2)^2 = -1/2(y-13). To find the x-intercepts, let y=0.

(x-2)^2 = -1/2(0-13) = 6.5
x-2 = +/- √6.5 = +/- 2.55
x = 4.55 and and -0.55

The x-intercepts are (-0.55,0) and (4.55,0).

Answer:

(-0.55,0),(4.55,0)

The path of a ping pong ball that is hit from one end of the table can be modeled by the equation (y= -1/4 x^2 5x) where x is measured in inches and represents the horizontal distance from the edge of the table, and y represents the height of the ping pong ball in inches above the table. What is the maximum height of the ping pong ball?

A.
The ball reaches a maximum height of 30 inches above the table.
B.
The ball reaches a maximum height of 20 inches above the table.
C.
The ball reaches a maximum height of 25 inches above the table.
D.
The ball reaches a maximum height of 27 inches above the table.

Answers

There is something missing in the given model equation. I think the correct equation is y= -1/4 x^2 + 5x. You maybe forgot to type the '+' sign. I checked it initially, and I got an answer that's in the choices. So, hopefully, this is correct.

To find the maximum height, you must solve this equation through differential calculus. To find the maxima or minima, you differentiate the equation y in terms of x and equate it to zero. 

y' = 2(-1/4)x + 5 = -1/2*x + 5 = 0

By doing this, you would solve the value of x or the horizontal distance.

-1/2*x = -5
x =-5*-2
x = 10 inches

Finally, we substitute this x to the original equation to determine the maximum height y.

y = -1/4*10 + 5(10)
y = 25 inches

The answer is C.

!!! HELP What values for (picture of equation) satisfy the equation?

Answers

The values of 0 ≤ θ ≤ 2π are π/6, π/4, π/3, π/2, 2π/3, 3π/4, 5π/6, π, 7π/6, 5π/4, 4π/3, 5π/3, 7π/4 and 11π/6. It can be inputted into trigonometric functions. Tangent is sine over cosine. Since sine and cosine are periodic, then tangent has to be, as well.–π to –π/2: The tangent will be zero wherever its numerator (the sine) is zero. This happens at 0, π, 2π, 3π, etc, and at –π, –2π, –3π, etc. The tangent will be undefined wherever its denominator (the cosine) is zero. A zero in the denominator means you'll have a vertical asymptote. So the tangent will have vertical asymptotes wherever the cosine is zero

A bakery sold apple pies for $11 and blueberry pies for $13. One Saturday they sold a total of 38 pies and collected a total of $460. How many apple pies did they sell and how many blueberry pies did they sell?

Answers

A= apple pie

B = blueberry pie

a+b=38

a=38-b

11a + 13b =460

11(38-b) + 13b = 460

418-11b +13b = 460

2b=42

b=42/2 =21

they sold 21 blueberry pies and 17 apple pies

17 Apple pies and 21 blueberry pies

If the factors of a polynomial are x-2 and x-5, what values of x make that polynomial 0?

A. 1 and 2
B. -2 and -5
C. 2 and 5
D. Cannot be determined

Answers

C since you just make the factors equal to 0. x-5=0 and x-2=0 and then you just solve for x

The number of hours walked varies inversely with the speed of the walker. if it takes sam 12 hours to complete his walking goal at 5 miles per hour, how long would it take him at 3 miles per hour?

Answers

We let k be the proportionality constant for the relationship between number of hours, h and speed of the walker, s. 

                        h = k/s
Substituting the known values,
                        12 = k/5
                          k = 60

For the second scenario,
                          h = k/s
Substituting the calculated value for k and the given value for speed,
                          h = (60)(3 miles/hour)
                         h = 20 hours
                         h = 20 hours

Therefore, it will take 20 hours to walk with a speed of 3 miles per hour. 

Best explained and correct answer gets brainliest.

Answers

total = 2372* (1+0.045)^20=

2372*1.045^20=

2372 * 2.411714025= 5720.585

she will have 5720.59 in 20 years

Please Help. Thank you

Answers

The answer is D. A translation does not change a figure's size or shape because each of its points are moved the same amount and in the same direction(s).

What is the area of the obtuse triangle given below?

Answers

the area of a triangle = 1/2 * b * h

A = 1/2 * 11 * 7 = 38.5

your answer is D

hope that helps :)

Answer:

Option (d) is correct.

The area of triangle is 38.5 square units

Step-by-step explanation:

 Given: An obtuse triangle.

We have to find the area of this obtuse angle.

Consider the given obtuse triangle

Area of triangle = [tex]\frac{1}{2}\cdot b \cdot h[/tex]

where b = Base

h = height

Given : base = 11  units

and height = 7 units

Thus, Area of triangle = [tex]\frac{1}{2}\cdot 11 \cdot 7[/tex]

Simplify, we have,

Area of triangle = 38.5

Thus, The area of triangle is 38.5 square units

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